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Author Topic: Short Commands in .bat files.  (Read 5263 times)

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  • Experienced user
  • Posts: 1251
Short Commands in .bat files.
« on: May 09, 2014, 02:13:39 AM »
1. If access/run an executable from RadioBOSS (e.g. PlaylistGeneratorPro.exe) we have to add the entire path and some shots must be between quotes:

Code: [Select]
"C:\Program Files\RadioBOSS\PlaylistGeneratorPro.exe" "-preset=Ittaly+Blues2+2" -out=E:\!_RadioBOSS\Playlists\Feb_%%nn.m3u8
2. If want to make 24 customized commands will be very difficult to check all paths and becouse the length of the command.


Insert the path of RadioBOSS in System Variables:

Code: [Select]
;C:\Program Files\RadioBOSS
How to (steps in Windows 7):

A. Windows PATH Variable

1. Control Panel -> System -> Advanced System Settings;
2. Tab Advanced -> Environment Variables... (right bottom button);
3. System variables -> Path -> Edit... button (or double click on "Path");
4. At the end of the "Variable value:" field add without space between characters a semicolon and your path of RadioBOSS. Mine is:

Code: [Select]
Yours could be:

Code: [Select]
;C:\Program Files\RadioBOSS
5. Click all "OK" buttons.

B. bat File

Now the command will be shorter and easier to read:

Code: [Select]
PlaylistGeneratorPro "-preset=ORA 00" -out=E:\!_RadioBOSS\Playlists\MAI10_00.m3u8

If you want another name instead PlaylistGeneratorPro make a copy of PlaylistGeneratorPro.exe and rename it as you wish. For example I renamed it as "Gen.exe". So my command in bat file is:

Code: [Select]
Gen  "-preset=ORA 00" -out=E:\!_RadioBOSS\Playlists\MAI10_00.m3u8
« Last Edit: May 09, 2014, 07:46:43 AM by pety »